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Is it possible?

To: Aquatic-Plants at actwin_com
Subject: Is it possible?
From: Ricky Wai Wah Leung <kfrickie at HK_Super.NET>
Date: Wed, 16 Jul 1997 17:47:30 +0800 (HKT)


Dear friends,

With the equations stated with George and other fellow,

 mg/L CO2 = 1.60 X 10^(6.0-pH) X mg/L HCO3-

or-
>                      HCO3-      CO2
>    pH = 6.37 + log [ ------ = ------- ]
>                      H2CO3   1.64CaCO3

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