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Calculations OK?
*2nd*
I managed to get hold of a UK based product by the name of LIBREL.
It is a chelated trace element mix consisting of
1.7% Cu
3.35% Fe
1.70% Mn
0.60% Zn
0.875% B
0.023% Mo
The stuff is nicely package in a 1 kg pack (smallest). However, since
the nutrients ratio are non-identical to that of PMDD's recipe, I need
some helping hand to confirm whether my calculations are correct.
1) Dissolving 1 gram of LIBREL in 1000 litre of water will give a
concentration of Fe = 0.035 ppm
2) In the Sears-Conlin paper at
http://www.thekrib.com/Plants/Fertilizer/sears-conlin.html
under RECOMMENDATIONS paragraph four item 2:
the ratio of Mg to Fe was recommended at 1.5-5.0ppm Mg to 1ppm Fe.
Under APPENDIX A - FERTILIZER RECIPE (Poor Man's Dupla Drops) of
9 grams of trace mix (7% Fe...) is supposed to be mixed with
14 grams K2S04
6g grams KNO3
33 grams MgSO4.7H2O
a) If the above stuff are mixed into 1000 litre of water,
we will get a concentration of Fe = 0.07 x 9 = 0.63 ppm
b) Dissolving 1 gm of MgSO4.7H2O into 1000 litre of water will produce
a concentration of Mg = 0.0987 ppm. 33 grams will produce 33 x 0.0987
= 3.2571ppm
Ratio of Mg to Fe = 3.2571 / 0.63 = 5.17
Therefore, 2) above is correct, IF and ONLY IF my calculations are OK :(
3)
a)1 gram of LIBREL will produce a concentration of Fe = 0.035 ppm
to get 0.63ppm Fe, I need 0.63 / 0.035 = 18 grams of LIBREL
b) I think the volume of MgSO4, KNO3 and K2SO4 still remains. THEREFOR
I need:
18 grams of LIBREL chelated trace element mix
14 grams K2SO4
6 grams KNO3
33 grams MgSO4.7H2O
300ml distilled water
Appreciate if somebody can endorse my calculations.
Thank you.
Daud Datu
Brunei
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