[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

Re: [APD] Re: Bubbles? -- or - The results are in!

So, I made the needed modifications to my reactor tonight. Made a quick trip over to Home Depot and picked up the necessary parts. I've put up a few pics that can be seen here:
http://www.terrellclan.com/reactor.html
It's a handful of pics, so you dial-up go-ers, heads up!

And the verdict? Well, I don't know yet, I can say two joints aren't water tight and will need some sealing somehow. They're barely leaking anything, but it also implies air could be getting in. I definitely want to use the clear piece, but I'll just have to see if it's possible.

I also want to modify it so that there is a 'burp' valve at the top to get rid of built up extra gases. It works much better now, so to everyone I extend my greatest thanks!

As far as breakdown of price, you just can't beat the DIY method. Overall I spent:

~$14.00 - PVC tube, fittings, etc.
~2hrs work (less if you do it right the first time)

That doesn't include the clear tube, that was a gravel vac tube I had that happens to fit very well (but is slightly leaking, nothing some silicon glue won't fix). Also doesn't include the handful of bio balls I used and the nylon tube. Overall you could have this thing really cheap, and I hope to see good results from it, and from what I hear it should do a great job!

Thanks a bunch!

-Dave T.


David Terrell wrote:
Bah yes, I didn't out the Pi in the equation

Pi (2r)^2     Pi 4r^2
--------- ->  -------  take out r^2 and pi (common) = 4
Pi r^2        Pi r^2

Definately need a refresher, or to take my time.  Can't do math like I
used to :-(

On 2/4/2004, "Andrew Mitchell" <andrewm at cse_unsw.edu.au> wrote:


On Thu, 2004-02-05 at 07:02, David Terrell wrote:

You know, I think I just need a refresher geometry class, UGH!  Volume
isn't increasing by 2Pi :-(  The circumference does!  I'll do some quick
math.  r is the old radius, R is the new radius (R=2r).  So, if
v=Pi*r^2, and R=2r, then dv=Pi*4!  HAH, that means a 1.5" pipe has
~12.57 times more volume then a 0.75" pipe of the same length.  Now I'm
really starting to think this thing will work ;-)  Man, someone stop me
if I'm wrong!

-Dave T. (mumbling to himself, 'a^2+b^2=c^2, garblegarblegarble') 

um, doubling the diameter should quadruple the area (divide the flow by
4 in the case of your reactor assuming that your flow rate is limited
by tubing elsewhere in the system)

Area1=Pi*r^2
Area2=Pi*(2*r)^2
   =Pi* 2^2 * r^2
Area2/Area1=4, not 4*pi

--
Andrew Mitchell <andrew at andrewmitchell_id.au>

_______________________________________________
Aquatic-Plants mailing list
Aquatic-Plants at actwin_com
http://www.actwin.com/mailman/listinfo.cgi/aquatic-plants



_______________________________________________
Aquatic-Plants mailing list
Aquatic-Plants at actwin_com
http://www.actwin.com/mailman/listinfo.cgi/aquatic-plants


_______________________________________________
Aquatic-Plants mailing list
Aquatic-Plants at actwin_com
http://www.actwin.com/mailman/listinfo.cgi/aquatic-plants