# Re: NFC: Peltier Junction Cooling

```Sanitation engineer, perhaps?  ;-)
>
> Ouch! I am a darn engineer and all this thermodynamics scares me. Good
> thing I am not a Chemical or Mechanical engineer, huh?
>
> On Fri, 8 Jan 1999, Andrew S Dalton wrote:
> > >>Electrical work:  W = VA = 12*8.5 = 102 watts.
> > >>W/Q >= 1 - Tc/Th, so Q <= W/(1 - Tc/Th).
> > >>Tc = (0 + 273) K = 273 K.  Th = (50 + 273) K = 323 K.
> > >>Therefore, Q <= 102 watts/(1 - 273/323) = 659 watts.
> > >>
> > (20 gal H2O)(8.5 lb H2O/gal)(1 Btu/lb H2O/deg F)(80 deg F - 60 deg F) =
> > 3400 Btu.
> >
> > The amount of time needed to go from 60 to 80 deg F would be:
> > 3400 Btu/(171 Btu/hr) = 19.9 hr.
> >
> > Mathematically:  Q = U*A*(To - Ti).
> >
>
> --
>
>

Prost,

Martin

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```

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