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Re: NFC: Peltier Junction Cooling

To: nfc at actwin_com
Subject: Re: NFC: Peltier Junction Cooling
From: "D. Martin Moore" <archimedes at master_localink4.com>
Date: Sun, 10 Jan 1999 01:37:06 -0600
In-reply-to: <Pine.A41.3.96.990108195206.379470B-100000 at tigger_cc.uic.edu>
References: <003c01be3b64$cd9c6620$f0296420@asdalton>

Sanitation engineer, perhaps?  ;-)
> 
> Ouch! I am a darn engineer and all this thermodynamics scares me. Good
> thing I am not a Chemical or Mechanical engineer, huh? 
> 
> On Fri, 8 Jan 1999, Andrew S Dalton wrote:
> > >>Electrical work:  W = VA = 12*8.5 = 102 watts.
> > >>W/Q >= 1 - Tc/Th, so Q <= W/(1 - Tc/Th).
> > >>Tc = (0 + 273) K = 273 K.  Th = (50 + 273) K = 323 K.
> > >>Therefore, Q <= 102 watts/(1 - 273/323) = 659 watts.
> > >>
> > (20 gal H2O)(8.5 lb H2O/gal)(1 Btu/lb H2O/deg F)(80 deg F - 60 deg F) =
> > 3400 Btu.
> > 
> > The amount of time needed to go from 60 to 80 deg F would be:
> > 3400 Btu/(171 Btu/hr) = 19.9 hr.
> > 
> > Mathematically:  Q = U*A*(To - Ti).
> > 
> 
> --
> Sajjad Lateef                         <http://www.eecs.uic.edu/~slateef>
> sajjad at acm_org      Please Visit NFC: <http://nativefish.interspeed.net>
> 
> 


Prost,

Martin

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References:

Re: NFC: Peltier Junction Cooling

From: "Andrew S Dalton" <ASDALTON at prodigy_net>

Re: NFC: Peltier Junction Cooling

From: Sajjad Lateef <sajjad at uic_edu>

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