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Re: Aquatic Plants Digest V3 #233
Hi, Jim,
You are right, that 55 g is not 121 lbs. - it is just under 2 oz.
One crucial information has been omitted from the recipe: In what volume
of water are these trace elements supposed to be dissolved? One would
assume that it would be 1 Liter, but it's nice to know for certain.
Also, the dose is not stated - how many drops, milliliters, tablespoons,
etc. of this solution are to be added to a gallon of aquarium water.
On the practical side: Only someone with access to a laboratory with an
analytical balance can weigh out 25 mg (that's about 0.001 oz!) of
copper & cobalt salts accurately. Excess copper will harm the fish & and
probably will not be good for plants either.
Best,
George
Jim Wilson wrote:
>
> Date: Tue, 28 Apr 1998 17:37:57 -0700
> From: Jim Wilson <freaks at aracnet_com>
> Subject: more ?'s on trace elements
>
> I found this recipe in the archives:
>
> EDTA sodium ferric salt (chelated iron) 40.000g = 7.70% Fe 7.00%
> MnCl2.4H2O (manganese) 10.000g = 4.56% Mn 2.00%
> H3BO3 (boron) 3.000g = 0.85% B 1.30%
> ZnSO4.7H2O (zinc) 2.000g = 0.73% Zn 0.40%
> Na2MoO4.2H2O (molybdenum) 0.250g = 0.16% Mo 0.06%
> CuSO4.5H2O (copper) 0.025g = 0.01% Cu 0.10%
> CoCl2.6H2O (cobalt) 0.025g = 0.01% Co
> total 55.300g
>
> Has anyone tried this? Is it equal to chelated trace elements?
> 55.3g is 121 lbs, that's a lot!!! Could quarter it:
>
> EDTA sodium ferric salt (chelated iron) 10.0g
> MnCl2.4H2O (manganese) 2.5g
> H3BO3 (boron) 0.75g
> ZnSO4.7H2O (zinc) 0.5g
> Na2MoO4.2H2O (molybdenum) 0.0625g
> CuSO4.5H2O (copper) 0.00625g
> CoCl2.6H2O (cobalt) 0.00625g
> total 13.825g
> ?
>
> enjoying the sun in portland
> jim
>
> Date: Tue, 28 Apr 1998 21:46:12 -0700
> From: Jim Wilson <freaks at aracnet_com>
> Subject: too much time online (was more ?'s on trace elements)
>
> Well hopefully this will make it on to the same issue as my previous post.
> In which i said :
>
> "55.3g is 121 lbs, that's a lot!!! Could quarter it"
>
> Well now I show my inadequacy due to being a citizen of the united states.
> In not learning the metric system. "g" = gram and 1000g's in a K which
> equals 2.2 lbs. Not 2.2 lbs to the gram. duh?????
>
> frying my brain by spending way too much time online,
> jim