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Re: [APD] hydrogen peroxide dosage

Jerry Baker wrote:
> I have a 125 US gallon tank (473L). That means I want 473L * 15mg/L = 
> 7,095mg of H2O2, or 7.095g. How much of a 6% H2O2 solution do I need to 
> add in order to have 7.095g? We know there are 60g/L, so we just divide 
> (60g/L)/7.095g = 0.118L or 118mL (about 8 tablespoons).

One day I will learn to proofread *before* I send. At least it's only a 
formulaic error this time ... 7.095g/(60 g/L).
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