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Re: [APD] Re: Bubbles? -- or - The results are in!
--- David Terrell <Dave at terrellclan_com> wrote:
> So, I made the needed modifications to my reactor
> tonight. . . .I've put up
> a few pics that can be seen here:
> It's a handful of pics, so you dial-up go-ers, heads up!
> . . .I also want to modify it so that there is a 'burp'
> at the top to
> get rid of built up extra gases.
With any luck, it won't be necessary. When things are
operating well, there should not be a continuous increase
in the amount of gas in the reactor.
But if you want one, any well made microvalve will work.
You can try to thread one into a small whole in the PVC,
but it will be hard to have it not leak -- there's always
epoxy. Plastic microvalves will work but if they are not
clsoed jsut right, they have a slight tendency to leak.
That's my experience anyhow using them on u-tubes on
over-the-rim overflow boxes.
> . . .
> ~$14.00 - PVC tube, fittings, etc.
> ~2hrs work (less if you do it right the first time)
> That doesn't include the clear tube, that was a gravel
> vac tube I had
Clear PVC is very expensive, 2" stuff can be $2-$3 per foot
and usually *not* sold in 1 or 2 foot increments.
Clear acrylic, much cheaper than PVC, can work if you can
find the right size.
This place sells some:
So does Usplastics.com :
> that happens to fit very well (but is slightly leaking,
> nothing some
> silicon glue won't fix). Also doesn't include the
> handful of bio balls
> I used and the nylon tube. Overall you could have this
> thing really
> cheap, and I hope to see good results from it, and from
> what I hear it
> should do a great job!
> Thanks a bunch!
> -Dave T.
> David Terrell wrote:
> > Bah yes, I didn't out the Pi in the equation
> > Pi (2r)^2 Pi 4r^2
> > --------- -> ------- take out r^2 and pi (common) = 4
> > Pi r^2 Pi r^2
> > Definately need a refresher, or to take my time. Can't
> do math like I
> > used to :-(
> > On 2/4/2004, "Andrew Mitchell"
> <andrewm at cse_unsw.edu.au> wrote:
> >>On Thu, 2004-02-05 at 07:02, David Terrell wrote:
> >>>You know, I think I just need a refresher geometry
> class, UGH! Volume
> >>>isn't increasing by 2Pi :-( The circumference does!
> I'll do some quick
> >>>math. r is the old radius, R is the new radius
> (R=2r). So, if
> >>>v=Pi*r^2, and R=2r, then dv=Pi*4! HAH, that means a
> 1.5" pipe has
> >>>~12.57 times more volume then a 0.75" pipe of the same
> length. Now I'm
> >>>really starting to think this thing will work ;-)
> Man, someone stop me
> >>>if I'm wrong!
> >>>-Dave T. (mumbling to himself, 'a^2+b^2=c^2,
> >>um, doubling the diameter should quadruple the area
> (divide the flow by
> >>4 in the case of your reactor assuming that your flow
> rate is limited
> >>by tubing elsewhere in the system)
> >> =Pi* 2^2 * r^2
> >>Area2/Area1=4, not 4*pi
> >>Andrew Mitchell <andrew at andrewmitchell_id.au>
> >>Aquatic-Plants mailing list
> >>Aquatic-Plants at actwin_com
> > _______________________________________________
> > Aquatic-Plants mailing list
> > Aquatic-Plants at actwin_com
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> Aquatic-Plants at actwin_com
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