Re: [APD] Help with Ca and Mg calculations

[dbertot at pluspetrol_com.ar]

Hi Daniel:
Given tha almos all test kits only measures Ca and Mg ions and that a
general expression used to calculate water hardness is:

hardness = 2.5(Ca2+) + 4.1(Mg2+)

an considering that you know how much Mg there is in your water and its
total hardness, the content of Ca should be:

3.6*17.9=2.5(Ca2+)+4.1 (2.3 ppm)

64.44 ppm=2.5(Ca2+)+9.43 ppm

64.44 ppm-9.43 ppm=2.5(Ca2+)

55.01ppm/2.5=(Ca2+)

22ppm=(Ca2+)

According to this your content of Ca is 22 ppm

I hope this help you

Diego
Burzaco Argenitna







"Daniel Larsson" <defdac at hotmail_com> on 11/20/2003 03:47:52 PM

Please respond to aquatic plants digest <aquatic-plants at actwin_com>

To:   Aquatic-Plants at actwin_com
cc:    (bcc: Diego A Bertot/ADMIN/BAIRES/ARG/PLUSP)
Subject:  [APD] Help with Ca and Mg calculations



Hello folks!

I have a problem. I want to know Ca in ppm, but only knows these
values:

Total hardness: 3,6 dH
Alkalinity, HCO3: 55 mg/l
Mg: 2.3 mg/l
Na: 19 mg/l
Cl: 11 mg/l
F: 0,13 mg/l
Conductivity: 18,2 mS/m

Is it possible to derive Ca-content from these values? If so, I would
love to know the Ca-content in ppm 8)


// Daniel.
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